What is x^2+y^2-3x+8y=20 ?

The solution to x^2+y^2-3x+8y=20 is Circle with (a,b)=(3/2 ,-4),r=(3sqrt(17))/2

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x^2+y^2-3x+8y=20

x^{2} + y^{2} - 3 x + 8 y = 20

(a, b) = (\frac{3}{2}, - 4), r = \frac{3 17}{2}

Solution steps

x^{2} + y^{2} - 3 x + 8 y = 20

Rewrite

x^{2} + y^{2} - 3 x + 8 y = 20

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 4))^{2} = (\frac{3 17}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 4), r = \frac{3 17}{2}

x^{2} + y^{2} - 12 x - 10 y + 52 = 0

x^{2} + y^{2} - 12 x + 14 y + 36 = 0

x^{2} + y^{2} - 8 x - 8 y + 28 = 0

2 x^{2} + 3 x + 2 y^{2} + 7 y = 19

(x + 4)^{2} + (y - 1)^{2} = 148

What is x^2+y^2-3x+8y=20 ?
The solution to x^2+y^2-3x+8y=20 is Circle with (a,b)=(3/2 ,-4),r=(3sqrt(17))/2