What is x^2+y^2-10x+26y+167=0 ?

The solution to x^2+y^2-10x+26y+167=0 is Circle with (a,b)=(5,-13),r=3sqrt(3)

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x^2+y^2-10x+26y+167=0

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

(a, b) = (5, - 13), r = 33

Solution steps

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

Rewrite

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 13))^{2} = (33)^{2}

Therefore the circle properties are:

(a, b) = (5, - 13), r = 33

(x + 4)^{2} + (y + 1)^{2} = 9

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

3 x^{2} + 3 y^{2} - 3 x - 3 y - 9 = 0

(x - 6)^{2} + (y + 2)^{2} = 16

x^{2} - 8 x + 16 + y^{2} - 4 y + 4 = (34)^{2}

What is x^2+y^2-10x+26y+167=0 ?
The solution to x^2+y^2-10x+26y+167=0 is Circle with (a,b)=(5,-13),r=3sqrt(3)