What is (-7-p)^2+(0-q)^2=625 ?

The solution to (-7-p)^2+(0-q)^2=625 is Circle with (a,b)=(-7,0),r=25

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(-7-p)^2+(0-q)^2=625

(- 7 - p)^{2} + (0 - q)^{2} = 625

(a, b) = (- 7, 0), r = 25

Solution steps

(- 7 - p)^{2} + (0 - q)^{2} = 625

Rewrite

(- 7 - p)^{2} + (0 - q)^{2} = 625

in the form of the standard circle equation

(p - (- 7))^{2} + (q - 0)^{2} = 2 5^{2}

Therefore the circle properties are:

(a, b) = (- 7, 0), r = 25

(2 x)^{2} + (2 y - 1)^{2} = 4^{2}

x^{2} + 20 x + y^{2} + 16 = - 20

x^{2} - 8 x + y^{2} + 4 y - 5 = 0

2 x^{2} + 2 y^{2} - 1 = 0

x^{2} - 14 x + y^{2} + 8 y + 53 = 0

What is (-7-p)^2+(0-q)^2=625 ?
The solution to (-7-p)^2+(0-q)^2=625 is Circle with (a,b)=(-7,0),r=25