What is (x-5/4)^2+(y+9/2)^2=14 ?

The solution to (x-5/4)^2+(y+9/2)^2=14 is Circle with (a,b)=(5/4 ,-9/2),r=sqrt(14)

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(x-5/4)^2+(y+9/2)^2=14

(x - \frac{5}{4})^{2} + (y + \frac{9}{2})^{2} = 14

(a, b) = (\frac{5}{4}, - \frac{9}{2}), r = 14

Solution steps

(x - \frac{5}{4})^{2} + (y + \frac{9}{2})^{2} = 14

Rewrite

(x - \frac{5}{4})^{2} + (y + \frac{9}{2})^{2} = 14

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - (- \frac{9}{2}))^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, - \frac{9}{2}), r = 14

x^{2} - 8 x + y^{2} = 0

x^{2} + y^{2} - 8 y + 12 = 0

(x - 6)^{2} + (y - 10)^{2} = (5)^{2}

(x + 6)^{2} + (y + 8)^{2} = 100

3 x^{2} + 3 y^{2} - 12 x - 24 y + 12 = 0

What is (x-5/4)^2+(y+9/2)^2=14 ?
The solution to (x-5/4)^2+(y+9/2)^2=14 is Circle with (a,b)=(5/4 ,-9/2),r=sqrt(14)