What is 4x^2+36x+4y^2+4y=318 ?

The solution to 4x^2+36x+4y^2+4y=318 is Circle with (a,b)=(-9/2 ,-1/2),r=10

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4x^2+36x+4y^2+4y=318

4 x^{2} + 36 x + 4 y^{2} + 4 y = 318

(a, b) = (- \frac{9}{2}, - \frac{1}{2}), r = 10

Solution steps

4 x^{2} + 36 x + 4 y^{2} + 4 y = 318

Rewrite

4 x^{2} + 36 x + 4 y^{2} + 4 y = 318

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - (- \frac{1}{2}))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, - \frac{1}{2}), r = 10

x^{2} + y^{2} - 12 x + 4 y + 15 = 0

3 x^{2} + 3 y^{2} - 12 x + 15 y - 21 = 0

(x + 1)^{2} + y^{2} = 16

x^{2} + y^{2} - 14 x - 8 y + 65 = 25

x^{2} + 16 x + 64 + y^{2} - 2 y + 1 = 144

What is 4x^2+36x+4y^2+4y=318 ?
The solution to 4x^2+36x+4y^2+4y=318 is Circle with (a,b)=(-9/2 ,-1/2),r=10