What is -2x^2-36x-2y^2-122=0 ?

The solution to -2x^2-36x-2y^2-122=0 is Circle with (a,b)=(-9,0),r=2sqrt(5)

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-2x^2-36x-2y^2-122=0

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

(a, b) = (- 9, 0), r = 25

Solution steps

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

Rewrite

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 0)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- 9, 0), r = 25

x^{2} + y^{2} - x + 6 y = 1

(x + 4)^{2} + (y - 7)^{2} = 25

x^{2} + y^{2} + 4 x - 2 y + 1 > 0

(x + 8)^{2} + (y - 4)^{2} = 20

x^{2} + y^{2} - 4 x - 8 y + 19 = 0

What is -2x^2-36x-2y^2-122=0 ?
The solution to -2x^2-36x-2y^2-122=0 is Circle with (a,b)=(-9,0),r=2sqrt(5)