What is (x+1/9)^2+(y-2/5)^2=169 ?

The solution to (x+1/9)^2+(y-2/5)^2=169 is Circle with (a,b)=(-1/9 , 2/5),r=13

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(x+1/9)^2+(y-2/5)^2=169

(x + \frac{1}{9})^{2} + (y - \frac{2}{5})^{2} = 169

(a, b) = (- \frac{1}{9}, \frac{2}{5}), r = 13

Solution steps

(x + \frac{1}{9})^{2} + (y - \frac{2}{5})^{2} = 169

Rewrite

(x + \frac{1}{9})^{2} + (y - \frac{2}{5})^{2} = 169

in the form of the standard circle equation

(x - (- \frac{1}{9}))^{2} + (y - \frac{2}{5})^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{9}, \frac{2}{5}), r = 13

(x + 1.5)^{2} + (y - 1)^{2} = 0.5

4 = (x + 2)^{2} + (y - 1)^{2}

x^{2} + 4 x + y^{2} - 8 y = - 16

x^{2} + y^{2} + 2 x - 4 y = 44

(x - 3)^{2} + (y + 2)^{2} = 2^{2}

What is (x+1/9)^2+(y-2/5)^2=169 ?
The solution to (x+1/9)^2+(y-2/5)^2=169 is Circle with (a,b)=(-1/9 , 2/5),r=13