What is x^2+y^2+8x-6y+10=0 ?

The solution to x^2+y^2+8x-6y+10=0 is Circle with (a,b)=(-4,3),r=sqrt(15)

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x^2+y^2+8x-6y+10=0

x^{2} + y^{2} + 8 x - 6 y + 10 = 0

(a, b) = (- 4, 3), r = 15

Solution steps

x^{2} + y^{2} + 8 x - 6 y + 10 = 0

Rewrite

x^{2} + y^{2} + 8 x - 6 y + 10 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 3)^{2} = (15)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 3), r = 15

x^{2} + y^{2} - 14 x + 12 y - 36 = 0

x^{2} + y^{2} + 6 x - 10 y + 17 = 0

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

x^{2} + y^{2} + \frac{4 ( x ^{2} + y ^{2} )}{21} = 25

x^{2} + z^{2} - 3 x - 6 z + 8 = 0

What is x^2+y^2+8x-6y+10=0 ?
The solution to x^2+y^2+8x-6y+10=0 is Circle with (a,b)=(-4,3),r=sqrt(15)