What is (x-15)^2+(y+20)^2=(9)^2 ?

The solution to (x-15)^2+(y+20)^2=(9)^2 is Circle with (a,b)=(15,-20),r=9

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(x-15)^2+(y+20)^2=(9)^2

(x - 15)^{2} + (y + 20)^{2} = (9)^{2}

(a, b) = (15, - 20), r = 9

Solution steps

(x - 15)^{2} + (y + 20)^{2} = 9^{2}

Rewrite

(x - 15)^{2} + (y + 20)^{2} = 9^{2}

in the form of the standard circle equation

(x - 15)^{2} + (y - (- 20))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (15, - 20), r = 9

x^{2} + y^{2} - 6 x - 4 y - 68 = 0

(x - 2)^{2} + (y - 4)^{2} = 81

(x - \frac{1}{4})^{2} + y^{2} = \frac{1}{16}

x^{2} + y^{2} + 10 x - 8 y - 8 = 0

- 1 = x^{2} + y^{2} - 6 x + 5

What is (x-15)^2+(y+20)^2=(9)^2 ?
The solution to (x-15)^2+(y+20)^2=(9)^2 is Circle with (a,b)=(15,-20),r=9