What is (x+1)^2+(y+6)^2=8^2 ?

The solution to (x+1)^2+(y+6)^2=8^2 is Circle with (a,b)=(-1,-6),r=8

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(x+1)^2+(y+6)^2=8^2

(x + 1)^{2} + (y + 6)^{2} = 8^{2}

(a, b) = (- 1, - 6), r = 8

Solution steps

(x + 1)^{2} + (y + 6)^{2} = 8^{2}

Rewrite

(x + 1)^{2} + (y + 6)^{2} = 8^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 6))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 6), r = 8

(x + 2)^{2} + (y - 3)^{2} = 10

(x - 7)^{(2)} + (y - 7)^{(2)} = \frac{( 4 )}{( 9 )}

(x - 2)^{2} + (y - 4)^{2} = 49

x^{2} - 9 + (y + 8)^{2} = 0

x^{2} + y^{2} + 2 x + 2 y - 4 = 0

What is (x+1)^2+(y+6)^2=8^2 ?
The solution to (x+1)^2+(y+6)^2=8^2 is Circle with (a,b)=(-1,-6),r=8