What is (x-1)^2+(y+5)^2=10 ?

The solution to (x-1)^2+(y+5)^2=10 is Circle with (a,b)=(1,-5),r=sqrt(10)

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(x-1)^2+(y+5)^2=10

(x - 1)^{2} + (y + 5)^{2} = 10

(a, b) = (1, - 5), r = 10

Solution steps

(x - 1)^{2} + (y + 5)^{2} = 10

Rewrite

(x - 1)^{2} + (y + 5)^{2} = 10

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 5))^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (1, - 5), r = 10

(x + 5)^{2} + (y - 4)^{2} = 9

(x - (- 4))^{2} + (y - 3)^{2} = 7

x^{2} + y^{2} - 16 x = 49

x^{2} + y^{2} + 12 x - 10 y + 45 = 0

(x + 5)^{2} + (y - 2)^{2} = 2

What is (x-1)^2+(y+5)^2=10 ?
The solution to (x-1)^2+(y+5)^2=10 is Circle with (a,b)=(1,-5),r=sqrt(10)