What is x^2+y^2+12x-10y=0 ?

The solution to x^2+y^2+12x-10y=0 is Circle with (a,b)=(-6,5),r=sqrt(61)

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x^2+y^2+12x-10y=0

x^{2} + y^{2} + 12 x - 10 y = 0

(a, b) = (- 6, 5), r = 61

Solution steps

x^{2} + y^{2} + 12 x - 10 y = 0

Rewrite

x^{2} + y^{2} + 12 x - 10 y = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 5)^{2} = (61)^{2}

Therefore the circle properties are:

(a, b) = (- 6, 5), r = 61

(x - 1)^{2} + (y - (- 3))^{2} = 2^{2}

x^{2} - 4 x - 3 + y^{2} + 10 y - 4 = 0

x^{2} + y^{2} = 5 3^{2}

x^{2} + y^{2} - 14 x - 18 y + 114 = 0

(x + 1)^{2} + (y - 2)^{2} = 100

What is x^2+y^2+12x-10y=0 ?
The solution to x^2+y^2+12x-10y=0 is Circle with (a,b)=(-6,5),r=sqrt(61)