What is 2x^2+2y^2-6x-14y-3=0 ?

The solution to 2x^2+2y^2-6x-14y-3=0 is Circle with (a,b)=(3/2 , 7/2),r=4

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2x^2+2y^2-6x-14y-3=0

2 x^{2} + 2 y^{2} - 6 x - 14 y - 3 = 0

(a, b) = (\frac{3}{2}, \frac{7}{2}), r = 4

Solution steps

2 x^{2} + 2 y^{2} - 6 x - 14 y - 3 = 0

Rewrite

2 x^{2} + 2 y^{2} - 6 x - 14 y - 3 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - \frac{7}{2})^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, \frac{7}{2}), r = 4

4 x^{2} + 4 y^{2} - 16 x + 12 y + 21 = 0

(x + 2)^{2} + (y + 2)^{2} = 3

(x + (- 3))^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 8 x + 2 y + 1 = 0

(x - 3)^{2} + (y - 5)^{2} = 1 4^{2}

What is 2x^2+2y^2-6x-14y-3=0 ?
The solution to 2x^2+2y^2-6x-14y-3=0 is Circle with (a,b)=(3/2 , 7/2),r=4