What is X^2+Y^2-20X-35Y+28=0 ?

The solution to X^2+Y^2-20X-35Y+28=0 is Circle with (a,b)=(10, 35/2),r=(sqrt(1513))/2

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X^2+Y^2-20X-35Y+28=0

X^{2} + Y^{2} - 20 X - 35 Y + 28 = 0

(a, b) = (10, \frac{35}{2}), r = \frac{1513}{2}

Solution steps

X^{2} + Y^{2} - 20 X - 35 Y + 28 = 0

Rewrite

X^{2} + Y^{2} - 20 X - 35 Y + 28 = 0

in the form of the standard circle equation

(X - 10)^{2} + (Y - \frac{35}{2})^{2} = (\frac{1513}{2})^{2}

Therefore the circle properties are:

(a, b) = (10, \frac{35}{2}), r = \frac{1513}{2}

x^{2} - 4 x + y^{2} - 5 = 0

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x^{2} + y^{2} - 8 x - 16 y + 55 = 0

(x - 2)^{2} + (y - 9)^{2} = 9

x^{2} + y^{2} + 2 x - 10 y + 10 = 0

What is X^2+Y^2-20X-35Y+28=0 ?
The solution to X^2+Y^2-20X-35Y+28=0 is Circle with (a,b)=(10, 35/2),r=(sqrt(1513))/2