What is (x-3)^2+(y-5)^2=9 ?

The solution to (x-3)^2+(y-5)^2=9 is Circle with (a,b)=(3,5),r=3

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(x-3)^2+(y-5)^2=9

(x - 3)^{2} + (y - 5)^{2} = 9

(a, b) = (3, 5), r = 3

Solution steps

(x - 3)^{2} + (y - 5)^{2} = 9

Rewrite

(x - 3)^{2} + (y - 5)^{2} = 9

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 3

y^{2} = 6 + x - x^{2}

(x - 17.1)^{2} + (y - 17.1)^{2} = 114

4^{2} = x^{2} + y^{2}

x^{2} + y^{2} = 0^{2}

(p + q) 2 = p^{2} + q^{2}

What is (x-3)^2+(y-5)^2=9 ?
The solution to (x-3)^2+(y-5)^2=9 is Circle with (a,b)=(3,5),r=3