What is (x-0)^2+(y-0)^2=10 ?

The solution to (x-0)^2+(y-0)^2=10 is Circle with (a,b)=(0,0),r=sqrt(10)

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(x-0)^2+(y-0)^2=10

(x - 0)^{2} + (y - 0)^{2} = 10

(a, b) = (0, 0), r = 10

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 10

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 10

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 10

9 x^{2} + 9 y^{2} - 6 x - 24 y = 19

x^{2} + y^{2} + 6 x + 8 y = 9

x^{(2)} + y^{(2)} + 4 x - 6 y - 12 = 0

x, x^{2} + Y (x)^{2} = 4

2 x^{2} + 2 y^{2} + 4 x - 3 y = - 2

What is (x-0)^2+(y-0)^2=10 ?
The solution to (x-0)^2+(y-0)^2=10 is Circle with (a,b)=(0,0),r=sqrt(10)