What is (2x^2-12x)+(2y^2+8y)=24 ?

The solution to (2x^2-12x)+(2y^2+8y)=24 is Circle with (a,b)=(3,-2),r=5

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(2x^2-12x)+(2y^2+8y)=24

(2 x^{2} - 12 x) + (2 y^{2} + 8 y) = 24

(a, b) = (3, - 2), r = 5

Solution steps

2 x^{2} - 12 x + (2 y^{2} + 8 y) = 24

Rewrite

2 x^{2} - 12 x + (2 y^{2} + 8 y) = 24

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 5

2 x^{2} + 2 y^{2} + 4 x - 8 y - 8 = 0

x^{(2)} + y^{(2)} = \frac{( 9 )}{( 4 )}

x^{2} + 12 x + y^{2} - 16 y = 0

(x - 3)^{2} + (y - 8)^{2} = 36

(x - 3)^{2} + (y - 8)^{2} = 34

What is (2x^2-12x)+(2y^2+8y)=24 ?
The solution to (2x^2-12x)+(2y^2+8y)=24 is Circle with (a,b)=(3,-2),r=5