What is (x-6)^{(2)}+(y+2)^{(2)}=5 ?

The solution to (x-6)^{(2)}+(y+2)^{(2)}=5 is Circle with (a,b)=(6,-2),r=sqrt(5)

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(x-6)^{(2)}+(y+2)^{(2)}=5

(x - 6)^{(2)} + (y + 2)^{(2)} = 5

(a, b) = (6, - 2), r = 5

Solution steps

(x - 6)^{2} + (y + 2)^{2} = 5

Rewrite

(x - 6)^{2} + (y + 2)^{2} = 5

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 2))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (6, - 2), r = 5

(x + 4)^{2} + (y + 1)^{2} = 30

x^{2} + y^{2} + 6 x - 8 y = - 24

y^{2} = 1 - 1 x^{2}

(x + 1)^{2} + (y + \frac{15}{8})^{2} = 5

x^{2} + y^{2} + 6 x + 4 = 3

What is (x-6)^{(2)}+(y+2)^{(2)}=5 ?
The solution to (x-6)^{(2)}+(y+2)^{(2)}=5 is Circle with (a,b)=(6,-2),r=sqrt(5)