What is (x+2)^2+(y-1.5)^2=(sqrt(2.75)i) ?

The solution to (x+2)^2+(y-1.5)^2=(sqrt(2.75)i) is Circle with (a,b)=(-2,1.5),r=sqrt(\sqrt{2.75)i}

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(x+2)^2+(y-1.5)^2=(sqrt(2.75)i)

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)

(a, b) = (- 2, 1.5), r = 2.75 i

Solution steps

(x + 2)^{2} + (y - 1.5)^{2} = 2.75 i

Rewrite

(x + 2)^{2} + (y - 1.5)^{2} = 2.75 i

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1.5), r = 2.75 i

(x + 2)^{2} + (y + 1)^{2} = 2

x^{2} + 4 x + y^{2} + 10 y = - 20

x^{2} + y^{2} + 10 x + 6 y - 47 = 0

x^{2} + y^{2} - 5 x = 3

(x - 1 + 23)^{2} + (y - 3)^{2} = 20

What is (x+2)^2+(y-1.5)^2=(sqrt(2.75)i) ?
The solution to (x+2)^2+(y-1.5)^2=(sqrt(2.75)i) is Circle with (a,b)=(-2,1.5),r=sqrt(\sqrt{2.75)i}