What is x^2+y^2+4x+2y-27=0 ?

The solution to x^2+y^2+4x+2y-27=0 is Circle with (a,b)=(-2,-1),r=4sqrt(2)

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x^2+y^2+4x+2y-27=0

x^{2} + y^{2} + 4 x + 2 y - 27 = 0

(a, b) = (- 2, - 1), r = 42

Solution steps

x^{2} + y^{2} + 4 x + 2 y - 27 = 0

Rewrite

x^{2} + y^{2} + 4 x + 2 y - 27 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 1))^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 1), r = 42

x^{2} + y^{2} = - 4 x - 3 y

(x - (- 4))^{2} + (y - (9))^{2} = 3^{2}

x^{2} + (y + 4)^{2} = 25

(x^{2} + 2 x + 1) + (y^{2} - 6 y + 9) = - 7 + 1 + 9

4 x^{(2)} + 40 x + 4 y^{(2)} - 32 y = 5

What is x^2+y^2+4x+2y-27=0 ?
The solution to x^2+y^2+4x+2y-27=0 is Circle with (a,b)=(-2,-1),r=4sqrt(2)