What is x^2+y^2-10x+2y+20=0 ?

The solution to x^2+y^2-10x+2y+20=0 is Circle with (a,b)=(5,-1),r=sqrt(6)

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x^2+y^2-10x+2y+20=0

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

(a, b) = (5, - 1), r = 6

Solution steps

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

Rewrite

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 1))^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (5, - 1), r = 6

(X + 8)^{2} + (Y + 6)^{2} = 100

(x^{2} + y^{2} - 1)^{2} > 9

9 x^{2} - 6 x + 9 + 9 y^{2} + 24 y + 144 = 19 + 9 + 144

(- 1 - x)^{2} + (2 - y)^{2} = 25

(x - 15)^{2} + (y + 7)^{2} = 7^{2}

What is x^2+y^2-10x+2y+20=0 ?
The solution to x^2+y^2-10x+2y+20=0 is Circle with (a,b)=(5,-1),r=sqrt(6)