What is x^2+y^2+6x-4y-36=0 ?

The solution to x^2+y^2+6x-4y-36=0 is Circle with (a,b)=(-3,2),r=7

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x^2+y^2+6x-4y-36=0

x^{2} + y^{2} + 6 x - 4 y - 36 = 0

(a, b) = (- 3, 2), r = 7

Solution steps

x^{2} + y^{2} + 6 x - 4 y - 36 = 0

Rewrite

x^{2} + y^{2} + 6 x - 4 y - 36 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = 7

(x + 2)^{2} + (y - 3)^{2} = 4^{2}

x^{(2)} + y^{(2)} + 2 x + 4 y - 15 = 0

(x - 3)^{2} + (y - 5)^{2} = 306.25

x^{2} + y^{2} - 8 x + 2 y + 10 = 0

(x + 1)^{2} + (y - 5)^{2} = 27

What is x^2+y^2+6x-4y-36=0 ?
The solution to x^2+y^2+6x-4y-36=0 is Circle with (a,b)=(-3,2),r=7