What is x^2+y^2=sqrt(13) ?

The solution to x^2+y^2=sqrt(13) is Circle with (a,b)=(0,0),r=sqrt(\sqrt{13)}

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x^2+y^2=sqrt(13)

x^{2} + y^{2} = 13

(a, b) = (0, 0), r = 13

Solution steps

x^{2} + y^{2} = 13

Rewrite

x^{2} + y^{2} = 13

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 13

x^{2} + y^{2} + 6 x + 5 y = \frac{45}{4}

(x - 1)^{(2)} + (y + 3)^{(2)} = 4

x^{2} + y^{2} + 2 x - 6 y + 1 + 9 - 9 = 0

x^{2} + y^{2} + 2 x + 2 y - 23 = 0

x^{2} + 14 x + 12 y + y^{2} = - 21

What is x^2+y^2=sqrt(13) ?
The solution to x^2+y^2=sqrt(13) is Circle with (a,b)=(0,0),r=sqrt(\sqrt{13)}