What is x^2+8x+16+y^2+4y+4=4 ?

The solution to x^2+8x+16+y^2+4y+4=4 is Circle with (a,b)=(-4,-2),r=2

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x^2+8x+16+y^2+4y+4=4

x^{2} + 8 x + 16 + y^{2} + 4 y + 4 = 4

(a, b) = (- 4, - 2), r = 2

Solution steps

x^{2} + 8 x + 16 + y^{2} + 4 y + 4 = 4

Rewrite

x^{2} + 8 x + 16 + y^{2} + 4 y + 4 = 4

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 2), r = 2

(x - 2)^{2} + (y + 4)^{2} = 3

(x + 8)^{2} + y^{2} = 1

x^{2} + y^{2} - 10 x + 10 y = 81

x^{2} + y^{2} \geq 36

(x - 2)^{2} + (y + 9)^{2} = 196

What is x^2+8x+16+y^2+4y+4=4 ?
The solution to x^2+8x+16+y^2+4y+4=4 is Circle with (a,b)=(-4,-2),r=2