What is x^2+y^2-5x=20-2y ?

The solution to x^2+y^2-5x=20-2y is Circle with (a,b)=(5/2 ,-1),r=(sqrt(109))/2

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x^2+y^2-5x=20-2y

x^{2} + y^{2} - 5 x = 20 - 2 y

(a, b) = (\frac{5}{2}, - 1), r = \frac{109}{2}

Solution steps

x^{2} + y^{2} - 5 x = 20 - 2 y

Rewrite

x^{2} + y^{2} - 5 x = 20 - 2 y

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- 1))^{2} = (\frac{109}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - 1), r = \frac{109}{2}

(x^{2} + 14 x 9) + (y^{2} + 12 y + 36) = 36 + 49 + 36

x^{2} + y^{2} - 10 x + 7 y + 30 = 0

x^{2} + 4 x + y^{2} + 6 y = 16

(x - 3)^{2} + (y + 2)^{2} = 33

4 x^{2} + 4 y^{2} - 24 x + 36 y = - 81

What is x^2+y^2-5x=20-2y ?
The solution to x^2+y^2-5x=20-2y is Circle with (a,b)=(5/2 ,-1),r=(sqrt(109))/2