What is (a+b)+(a-b)=a^2+b^2 ?

The solution to (a+b)+(a-b)=a^2+b^2 is Circle with (a,b)=(1,0),r=1

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(a+b)+(a-b)=a^2+b^2

(a + b) + (a - b) = a^{2} + b^{2}

(a, b) = (1, 0), r = 1

Solution steps

a + b + (a - b) = a^{2} + b^{2}

Rewrite

a + b + (a - b) = a^{2} + b^{2}

in the form of the standard circle equation

(a - 1)^{2} + (b - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 1

(x + 3)^{2} + (y + 2)^{2} = 36

x^{2} + y^{2} + 10 x - 12 y + 12 = 0

- y^{2} = (x + 2) (x - 3)

x^{2} - 4 x + y^{2} - 10 y = 35

(x_{+ 2})^{2} + (y + 1)^{2} = 16

What is (a+b)+(a-b)=a^2+b^2 ?
The solution to (a+b)+(a-b)=a^2+b^2 is Circle with (a,b)=(1,0),r=1