What is x^2+y^2=-8x-43-12y ?

The solution to x^2+y^2=-8x-43-12y is Circle with (a,b)=(-4,-6),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2=-8x-43-12y

x^{2} + y^{2} = - 8 x - 43 - 12 y

(a, b) = (- 4, - 6), r = 3

Solution steps

x^{2} + y^{2} = - 8 x - 43 - 12 y

Rewrite

x^{2} + y^{2} = - 8 x - 43 - 12 y

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 6))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 6), r = 3

(x - 1)^{2} + (y + 3)^{2} = 3

x^{2} + y^{2} - 5 x + 4 y = 16

x^{2} + 2 x + 1 + y^{2} + 4 y + 4 - 36 = 0

(x - 3)^{2} + (y - 4)^{2} - 9 = y - x + 1

(x - 1)^{2} + (y + 11)^{2} = 100

What is x^2+y^2=-8x-43-12y ?
The solution to x^2+y^2=-8x-43-12y is Circle with (a,b)=(-4,-6),r=3