What is (x+7)^2+(y+5)^2=50 ?

The solution to (x+7)^2+(y+5)^2=50 is Circle with (a,b)=(-7,-5),r=sqrt(50)

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(x+7)^2+(y+5)^2=50

(x + 7)^{2} + (y + 5)^{2} = 50

(a, b) = (- 7, - 5), r = 50

Solution steps

(x + 7)^{2} + (y + 5)^{2} = 50

Rewrite

(x + 7)^{2} + (y + 5)^{2} = 50

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 5))^{2} = (50)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 5), r = 50

x^{2} + y^{2} + 10 x - 16 y + 75 = 0

x^{2} + y^{2} - 10 x - 18 y + 81 = 0

x^{2} + y^{2} - 10 x + 2 y - 6 = 0

x^{2} + y^{2} - 6 x + 8 y = 8

x^{2} + y^{2} + 4 x - 2 y - 31 = 0

What is (x+7)^2+(y+5)^2=50 ?
The solution to (x+7)^2+(y+5)^2=50 is Circle with (a,b)=(-7,-5),r=sqrt(50)