What is (x^2-14x)+(y^2+2y)=-14 ?

The solution to (x^2-14x)+(y^2+2y)=-14 is Circle with (a,b)=(7,-1),r=6

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(x^2-14x)+(y^2+2y)=-14

(x^{2} - 14 x) + (y^{2} + 2 y) = - 14

(a, b) = (7, - 1), r = 6

Solution steps

x^{2} - 14 x + (y^{2} + 2 y) = - 14

Rewrite

x^{2} - 14 x + (y^{2} + 2 y) = - 14

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (7, - 1), r = 6

(x + 1)^{2} + (y - 1)^{2} = 4

(x - 4)^{2} + (y - 5)^{2} = 49

x^{2} + y^{2} = 6 x + 4 y - 1

x^{2} + y^{2} - 6 x - 8 y - 39 = 0

(x - 4)^{2} + (y + 6)^{2} = 36

What is (x^2-14x)+(y^2+2y)=-14 ?
The solution to (x^2-14x)+(y^2+2y)=-14 is Circle with (a,b)=(7,-1),r=6