What is (x)^2+(y)^2-6x+10y+34=72 ?

The solution to (x)^2+(y)^2-6x+10y+34=72 is Circle with (a,b)=(3,-5),r=6sqrt(2)

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(x)^2+(y)^2-6x+10y+34=72

(x)^{2} + (y)^{2} - 6 x + 10 y + 34 = 72

(a, b) = (3, - 5), r = 62

Solution steps

x^{2} + y^{2} - 6 x + 10 y + 34 = 72

Rewrite

x^{2} + y^{2} - 6 x + 10 y + 34 = 72

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 5))^{2} = (62)^{2}

Therefore the circle properties are:

(a, b) = (3, - 5), r = 62

a - b + a^{2} + b^{2} = 0

2 x^{2} - 4 x + 2 y^{2} + 18 y = 7

(x - 1)^{2} + y^{2} - 1 = \frac{3}{6} x

(x - 6)^{2} + (y - 10)^{2} = 5

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

What is (x)^2+(y)^2-6x+10y+34=72 ?
The solution to (x)^2+(y)^2-6x+10y+34=72 is Circle with (a,b)=(3,-5),r=6sqrt(2)