What is x^2+y^2-8x+2y=-1 ?

The solution to x^2+y^2-8x+2y=-1 is Circle with (a,b)=(4,-1),r=4

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x^2+y^2-8x+2y=-1

x^{2} + y^{2} - 8 x + 2 y = - 1

(a, b) = (4, - 1), r = 4

Solution steps

x^{2} + y^{2} - 8 x + 2 y = - 1

Rewrite

x^{2} + y^{2} - 8 x + 2 y = - 1

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 4

x^{2} + y^{2} - 4 y - 6 y = - 4

2 x^{2} + 2 y^{2} + 4 x - 8 y - 40 = 0

x^{2} + (y + 7)^{2} = 36

x^{2} + y^{2} - 8 x - 20 y + 67 = 0

x^{2} + y^{2} - 6 x = - 5

What is x^2+y^2-8x+2y=-1 ?
The solution to x^2+y^2-8x+2y=-1 is Circle with (a,b)=(4,-1),r=4