What is x^2-2x+y^2+4y=31 ?

The solution to x^2-2x+y^2+4y=31 is Circle with (a,b)=(1,-2),r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-2x+y^2+4y=31

x^{2} - 2 x + y^{2} + 4 y = 31

(a, b) = (1, - 2), r = 6

Solution steps

x^{2} - 2 x + y^{2} + 4 y = 31

Rewrite

x^{2} - 2 x + y^{2} + 4 y = 31

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 6

x^{2} + y^{2} - 4 x + 2 y + 2 = 0

x^{2} + y^{2} + 6 y + 3 = 0

x^{2} + y^{2} + x - \frac{1}{2} y = 0

(x - 0)^{2} + (y - 15)^{2} = 9

x^{2} - 2 x + y^{2} + 4 y = 43

What is x^2-2x+y^2+4y=31 ?
The solution to x^2-2x+y^2+4y=31 is Circle with (a,b)=(1,-2),r=6