What is x^2+y^2+16x+14y+104=0 ?

The solution to x^2+y^2+16x+14y+104=0 is Circle with (a,b)=(-8,-7),r=3

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x^2+y^2+16x+14y+104=0

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

(a, b) = (- 8, - 7), r = 3

Solution steps

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

Rewrite

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 7))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 7), r = 3

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

x^{2} - 2 y + y^{2} = 12

8 = x^{2} + y^{2}

x^{2} + y^{2} + 2 x - 2 y - 8 = 0

x^{2} + y^{2} - 12 x - 16 y + 36 = 0

What is x^2+y^2+16x+14y+104=0 ?
The solution to x^2+y^2+16x+14y+104=0 is Circle with (a,b)=(-8,-7),r=3