What is 0.59^2=(x-(-0.02))^2+(y-0.78)^2 ?

The solution to 0.59^2=(x-(-0.02))^2+(y-0.78)^2 is Circle with (a,b)=(-0.02,0.78),r=0.59

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0.59^2=(x-(-0.02))^2+(y-0.78)^2

0.5 9^{2} = (x - (- 0.02))^{2} + (y - 0.78)^{2}

(a, b) = (- 0.02, 0.78), r = 0.59

Solution steps

0.5 9^{2} = (x - (- 0.02))^{2} + (y - 0.78)^{2}

Rewrite

0.5 9^{2} = (x - (- 0.02))^{2} + (y - 0.78)^{2}

in the form of the standard circle equation

(x - (- 0.02))^{2} + (y - 0.78)^{2} = 0.5 9^{2}

Therefore the circle properties are:

(a, b) = (- 0.02, 0.78), r = 0.59

(x + \frac{23}{5})^{2} + (y - \frac{2}{5})^{2} = \frac{373}{5}

4 x^{2} + 4 y^{2} - 8 x + 16 y + 11 = 0

x^{2} + y^{2} + 2 x - 2 y = 18

(x + 7)^{2} + (y + 4)^{2} = 49

x^{2} - 8 x + y^{2} - 9 = 0

What is 0.59^2=(x-(-0.02))^2+(y-0.78)^2 ?
The solution to 0.59^2=(x-(-0.02))^2+(y-0.78)^2 is Circle with (a,b)=(-0.02,0.78),r=0.59