What is 36x^2+36y^2-48x-36y+16=0 ?

The solution to 36x^2+36y^2-48x-36y+16=0 is Circle with (a,b)=(2/3 , 1/2),r= 1/2

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36x^2+36y^2-48x-36y+16=0

36 x^{2} + 36 y^{2} - 48 x - 36 y + 16 = 0

(a, b) = (\frac{2}{3}, \frac{1}{2}), r = \frac{1}{2}

Solution steps

36 x^{2} + 36 y^{2} - 48 x - 36 y + 16 = 0

Rewrite

36 x^{2} + 36 y^{2} - 48 x - 36 y + 16 = 0

in the form of the standard circle equation

(x - \frac{2}{3})^{2} + (y - \frac{1}{2})^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{3}, \frac{1}{2}), r = \frac{1}{2}

3 x^{2} + 3 y^{2} - 15 - 0 = 0

x^{2} + 2 x + y^{2} - 8 y + 1 = 0

(x - 6)^{2} + (y - (- 2))^{2} = 25

x^{2} + y^{2} - 8 x - 1 y - 74 = 0

0.5 y^{2} = - 0.5 x^{2} + 12.5

What is 36x^2+36y^2-48x-36y+16=0 ?
The solution to 36x^2+36y^2-48x-36y+16=0 is Circle with (a,b)=(2/3 , 1/2),r= 1/2