What is x*x+y*y+5=2(3x-2y) ?

The solution to x*x+y*y+5=2(3x-2y) is Circle with (a,b)=(3,-2),r=2sqrt(2)

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xx+yy+5=2(3x-2y)

x \cdot x + y \cdot y + 5 = 2 (3 x - 2 y)

(a, b) = (3, - 2), r = 22

Solution steps

xx + yy + 5 = 2 (3 x - 2 y)

Rewrite

x \cdot x + y \cdot y + 5 = 2 (3 x - 2 y)

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 22

81 = x^{2} + y^{2}

\frac{x ^{2} + ( y ^{2} )}{36} = 1

2 x^{2} + 16 x + 2 y^{2} + 14 y = - \frac{77}{2}

1^{2} = (x - 0)^{2} + (y - 0)^{2}

x^{2} + y^{2} - 4 y - 15 = 6

What is x*x+y*y+5=2(3x-2y) ?
The solution to x*x+y*y+5=2(3x-2y) is Circle with (a,b)=(3,-2),r=2sqrt(2)