What is (x-4)^2+(y-7)^2=(sqrt(13))^2 ?

The solution to (x-4)^2+(y-7)^2=(sqrt(13))^2 is Circle with (a,b)=(4,7),r=sqrt((\sqrt{13))^2}

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(x-4)^2+(y-7)^2=(sqrt(13))^2

(x - 4)^{2} + (y - 7)^{2} = (13)^{2}

(a, b) = (4, 7), r = (13)^{2}

Solution steps

(x - 4)^{2} + (y - 7)^{2} = (13)^{2}

Rewrite

(x - 4)^{2} + (y - 7)^{2} = 13^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - 7)^{2} = ((13)^{2})^{2}

Therefore the circle properties are:

(a, b) = (4, 7), r = (13)^{2}

(x - 2)^{2} + (y + 7)^{2} = 16

x^{2} + y^{2} + 2 x - 6 y - 35 = 0

x^{2} + y^{2} - 2 x - 2 y - 9 = 0

x^{2} + 6 x + y^{2} - 8 y = 0

(x - 5)^{2} + (y + 2)^{2} = 85

What is (x-4)^2+(y-7)^2=(sqrt(13))^2 ?
The solution to (x-4)^2+(y-7)^2=(sqrt(13))^2 is Circle with (a,b)=(4,7),r=sqrt((\sqrt{13))^2}