What is (x-5)^2+(y+2)^2=64 ?

The solution to (x-5)^2+(y+2)^2=64 is Circle with (a,b)=(5,-2),r=8

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(x-5)^2+(y+2)^2=64

(x - 5)^{2} + (y + 2)^{2} = 64

(a, b) = (5, - 2), r = 8

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 64

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 64

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 8

9 (\frac{x - 3}{9})^{2} + 9 (\frac{y + 12}{9})^{2} = 172

(x - 1.5)^{2} + (y + 2.5)^{2} = 1.15

(x + 2)^{2} + (y - 8)^{2} = 4^{2}

(x - 40)^{2} + (y - 0)^{2} = 0.1

3 x^{2} - 2 x + 3 + 3 y^{2} + 8 y + 48 = \frac{172}{3}

What is (x-5)^2+(y+2)^2=64 ?
The solution to (x-5)^2+(y+2)^2=64 is Circle with (a,b)=(5,-2),r=8