What is (X+4)^2+(Y-1)^2=148 ?

The solution to (X+4)^2+(Y-1)^2=148 is Circle with (a,b)=(-4,1),r=sqrt(148)

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(X+4)^2+(Y-1)^2=148

(X + 4)^{2} + (Y - 1)^{2} = 148

(a, b) = (- 4, 1), r = 148

Solution steps

(X + 4)^{2} + (Y - 1)^{2} = 148

Rewrite

(X + 4)^{2} + (Y - 1)^{2} = 148

in the form of the standard circle equation

(X - (- 4))^{2} + (Y - 1)^{2} = (148)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 1), r = 148

(x + 2)^{2} + (y + 3)^{2} = 11

x^{2} + y^{2} + 4 x - 4 y = 1

(x + 2)^{2} + (y + 3)^{2} = 15

(x - 4)^{2} + (y - 3)^{2} = 64

x^{2} + y^{2} + 4 x + 12 y + 15 = 0

What is (X+4)^2+(Y-1)^2=148 ?
The solution to (X+4)^2+(Y-1)^2=148 is Circle with (a,b)=(-4,1),r=sqrt(148)