What is 9x^2+54x+9y^2-6y+28=0 ?

The solution to 9x^2+54x+9y^2-6y+28=0 is Circle with (a,b)=(-3, 1/3),r=sqrt(6)

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9x^2+54x+9y^2-6y+28=0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

(a, b) = (- 3, \frac{1}{3}), r = 6

Solution steps

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

Rewrite

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{1}{3})^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{1}{3}), r = 6

x^{2} + y^{2} + 6 x - 22 y + 66 = 0

x^{2} + y^{2} - 12 x + 24 y + 116 = 0

a^{2} = 5 - b^{2}

x^{2} + y^{2} - 2 \cdot x - 5.4 \cdot y + 7.29 = 0

2 x^{2} + 24 x + 2 y^{2} = 0

What is 9x^2+54x+9y^2-6y+28=0 ?
The solution to 9x^2+54x+9y^2-6y+28=0 is Circle with (a,b)=(-3, 1/3),r=sqrt(6)