What is x^{(2)}+y^{(2)}-6x-4y-9=0 ?

The solution to x^{(2)}+y^{(2)}-6x-4y-9=0 is Circle with (a,b)=(3,2),r=sqrt(22)

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x^{(2)}+y^{(2)}-6x-4y-9=0

x^{(2)} + y^{(2)} - 6 x - 4 y - 9 = 0

(a, b) = (3, 2), r = 22

Solution steps

x^{2} + y^{2} - 6 x - 4 y - 9 = 0

Rewrite

x^{2} + y^{2} - 6 x - 4 y - 9 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 22

\frac{8 x ^{2} - 12 x + 8 y ^{2} + 20 y + 17}{8} = 2

(x + 1)^{2} + (y - 4)^{2} = 16

x^{2} + (y - 3)^{2} = 100

(x - 15)^{2} + (y + 15)^{2} = 256

[5 (x + 4)]^{2} + 25 (y - 2)^{2} = 625

What is x^{(2)}+y^{(2)}-6x-4y-9=0 ?
The solution to x^{(2)}+y^{(2)}-6x-4y-9=0 is Circle with (a,b)=(3,2),r=sqrt(22)