What is x^2+y^2+6x-13y+13=0 ?

The solution to x^2+y^2+6x-13y+13=0 is Circle with (a,b)=(-3, 13/2),r=(3sqrt(17))/2

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x^2+y^2+6x-13y+13=0

x^{2} + y^{2} + 6 x - 13 y + 13 = 0

(a, b) = (- 3, \frac{13}{2}), r = \frac{3 17}{2}

Solution steps

x^{2} + y^{2} + 6 x - 13 y + 13 = 0

Rewrite

x^{2} + y^{2} + 6 x - 13 y + 13 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{13}{2})^{2} = (\frac{3 17}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{13}{2}), r = \frac{3 17}{2}

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(X + 7)^{2} + (y - 1)^{2} = 9

(x^{2} - 2) + (y^{2} + 4) = 4

What is x^2+y^2+6x-13y+13=0 ?
The solution to x^2+y^2+6x-13y+13=0 is Circle with (a,b)=(-3, 13/2),r=(3sqrt(17))/2