What is (x-3)^2+(y+1)^2=49 ?

The solution to (x-3)^2+(y+1)^2=49 is Circle with (a,b)=(3,-1),r=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-3)^2+(y+1)^2=49

(x - 3)^{2} + (y + 1)^{2} = 49

(a, b) = (3, - 1), r = 7

Solution steps

(x - 3)^{2} + (y + 1)^{2} = 49

Rewrite

(x - 3)^{2} + (y + 1)^{2} = 49

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 1))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (3, - 1), r = 7

(x + 7)^{2} + (y - 6)^{2} = 361

(x + 4)^{(2)} + (y - 2)^{(2)} = 25

\frac{x ^{2}}{6 ^{2}} + \frac{y ^{2}}{6 ^{2}} = 1

(x - 2)^{2} + (y + 3)^{2} = 4

x^{2} - 10 x + y^{2} + 4 y + 4 = 0

What is (x-3)^2+(y+1)^2=49 ?
The solution to (x-3)^2+(y+1)^2=49 is Circle with (a,b)=(3,-1),r=7