What is (4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1 ?

The solution to (4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1 is Circle with (a,b)=(-5/2 ,2),r=(3sqrt(5))/2

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(4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1

\frac{4 ( x + \frac{5}{2} ) ^{2}}{45} + \frac{4 ( y - 2 ) ^{2}}{45} = 1

(a, b) = (- \frac{5}{2}, 2), r = \frac{3 5}{2}

Solution steps

\frac{4 ( x + \frac{5}{2} ) ^{2}}{45} + \frac{4 ( y - 2 ) ^{2}}{45} = 1

Rewrite

\frac{4 ( x + \frac{5}{2} ) ^{2}}{45} + \frac{4 ( y - 2 ) ^{2}}{45} = 1

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 2)^{2} = (\frac{3 5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 2), r = \frac{3 5}{2}

x^{2} + (y - 1)^{2} = 2

x^{2} + (y - 1)^{2} = 7

x^{2} + (y + 5)^{2} = 61

x^{2} - 4 x + y^{2} - 6 y + 8 = 0

(x + 2)^{(2)} + (y - 1)^{(2)} = 3

What is (4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1 ?
The solution to (4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1 is Circle with (a,b)=(-5/2 ,2),r=(3sqrt(5))/2