What is x^2-18x+29+y^2=0 ?

The solution to x^2-18x+29+y^2=0 is Circle with (a,b)=(9,0),r=2sqrt(13)

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x^2-18x+29+y^2=0

x^{2} - 18 x + 29 + y^{2} = 0

(a, b) = (9, 0), r = 213

Solution steps

x^{2} - 18 x + 29 + y^{2} = 0

Rewrite

x^{2} - 18 x + 29 + y^{2} = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - 0)^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (9, 0), r = 213

3 x^{2} > 12 - 3 y^{2}

x^{2} + y^{2} - 16 x - 18 y + 109 = 0

(x - 4)^{2} + (y - 5)^{2} = 9

(x - 2)^{2} + y^{2} = 2

x^{2} + y^{2} + 4 x + 6 y = 16

What is x^2-18x+29+y^2=0 ?
The solution to x^2-18x+29+y^2=0 is Circle with (a,b)=(9,0),r=2sqrt(13)