What is (x^2+10x+25)+(y^2-2y+1)=9 ?

The solution to (x^2+10x+25)+(y^2-2y+1)=9 is Circle with (a,b)=(-5,1),r=3

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(x^2+10x+25)+(y^2-2y+1)=9

(x^{2} + 10 x + 25) + (y^{2} - 2 y + 1) = 9

(a, b) = (- 5, 1), r = 3

Solution steps

x^{2} + 10 x + 25 + (y^{2} - 2 y + 1) = 9

Rewrite

x^{2} + 10 x + 25 + (y^{2} - 2 y + 1) = 9

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 3

x^{(2)} + (y + 1)^{(2)} = 1

(x - 2)^{2} + (y - 1)^{2} = 5

(x - 2)^{2} + (y - 1)^{2} = 2

(x - 2)^{2} + (y - 3)^{2} = 1^{2}

(x + 2)^{2} + (y + 3)^{2} = 81

What is (x^2+10x+25)+(y^2-2y+1)=9 ?
The solution to (x^2+10x+25)+(y^2-2y+1)=9 is Circle with (a,b)=(-5,1),r=3