What is x^2+y^2+10x-2y=55 ?

The solution to x^2+y^2+10x-2y=55 is Circle with (a,b)=(-5,1),r=9

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x^2+y^2+10x-2y=55

x^{2} + y^{2} + 10 x - 2 y = 55

(a, b) = (- 5, 1), r = 9

Solution steps

x^{2} + y^{2} + 10 x - 2 y = 55

Rewrite

x^{2} + y^{2} + 10 x - 2 y = 55

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 9

4 x^{2} + 4 y^{2} - 16 y - 105 = 0

x^{2} + y^{2} + 4 x - 2 y = 1

x^{2} + y^{2} + 18 x + 17 = 0

(x - 4)^{2} + (y + 3)^{2} = 5^{2}

x^{2} - 11 x + y^{2} + 9 y + 15 = 0

What is x^2+y^2+10x-2y=55 ?
The solution to x^2+y^2+10x-2y=55 is Circle with (a,b)=(-5,1),r=9