What is x^2+(y-22.5)^2=22.5^2 ?

The solution to x^2+(y-22.5)^2=22.5^2 is Circle with (a,b)=(0,22.5),r=22.5

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x^2+(y-22.5)^2=22.5^2

x^{2} + (y - 22.5)^{2} = 22. 5^{2}

(a, b) = (0, 22.5), r = 22.5

Solution steps

x^{2} + (y - 22.5)^{2} = 22. 5^{2}

Rewrite

x^{2} + (y - 22.5)^{2} = 22. 5^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 22.5)^{2} = 22. 5^{2}

Therefore the circle properties are:

(a, b) = (0, 22.5), r = 22.5

x^{2} + y^{2} - 6 x - 8 y - 44 = 0

2 x^{2} + 2 y^{2} + 8 x + 20 y + 1 = 0

(x + 2)^{2} + (y + 5)^{2} = 64

(x - 12)^{2} + (y - 3)^{2} = 49

4 x^{2} + 4 y^{2} + 16 x + 24 y + 31 = 0

What is x^2+(y-22.5)^2=22.5^2 ?
The solution to x^2+(y-22.5)^2=22.5^2 is Circle with (a,b)=(0,22.5),r=22.5