What is x^2-8x+y^2-6y+25=1 ?

The solution to x^2-8x+y^2-6y+25=1 is Circle with (a,b)=(4,3),r=1

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x^2-8x+y^2-6y+25=1

x^{2} - 8 x + y^{2} - 6 y + 25 = 1

(a, b) = (4, 3), r = 1

Solution steps

x^{2} - 8 x + y^{2} - 6 y + 25 = 1

Rewrite

x^{2} - 8 x + y^{2} - 6 y + 25 = 1

in the form of the standard circle equation

(x - 4)^{2} + (y - 3)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (4, 3), r = 1

x^{2} + y^{2} + 6 x - 2 x - 2 y + 1 = 0

x^{2} + y^{2} - 6 x - 2 y = 15

x^{2} + 2 x + y^{2} - 6 y = 15

16 x^{2} + 80 x + 16 y^{2} - 112 y = - 247

x^{2} + y^{2} - 9 x + 4 y - 104 = 0

What is x^2-8x+y^2-6y+25=1 ?
The solution to x^2-8x+y^2-6y+25=1 is Circle with (a,b)=(4,3),r=1