What is X^2+Y^2-2X-4Y-36=0 ?

The solution to X^2+Y^2-2X-4Y-36=0 is Circle with (a,b)=(1,2),r=sqrt(41)

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X^2+Y^2-2X-4Y-36=0

X^{2} + Y^{2} - 2 X - 4 Y - 36 = 0

(a, b) = (1, 2), r = 41

Solution steps

X^{2} + Y^{2} - 2 X - 4 Y - 36 = 0

Rewrite

X^{2} + Y^{2} - 2 X - 4 Y - 36 = 0

in the form of the standard circle equation

(X - 1)^{2} + (Y - 2)^{2} = (41)^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 41

(x - 5)^{2} + (y + 4)^{2} = 16

x^{2} + y^{2} - 24 x - 8 y + 144 = 0

9 (x - 1)^{2} + 9 (y - 9)^{2} = 121

x^{2} - 2 x + y^{2} - 6 y = 0

(x - (- 1))^{2} + (y - (- 3))^{2} = 16

What is X^2+Y^2-2X-4Y-36=0 ?
The solution to X^2+Y^2-2X-4Y-36=0 is Circle with (a,b)=(1,2),r=sqrt(41)